• Rivalarrival@lemmy.today
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    1 year ago

    Your third axiom is faulty.

    Divisor, Dividend, Quotient. If your axiom is correct, then when I give you any two of these numbers, you should be able to give me the third. Yet when I give you an arbitrary quotient, and a divisor of 0, there is no dividend you can give me to complete the set.

    I can thus give you an infinite number of exceptions to your axiom.