Shady_Shiroe@lemmy.world to Programmer Humor@lemmy.ml · 1 year agoCall the Priestlemmy.worldimagemessage-square19fedilinkarrow-up123arrow-down13
arrow-up120arrow-down1imageCall the Priestlemmy.worldShady_Shiroe@lemmy.world to Programmer Humor@lemmy.ml · 1 year agomessage-square19fedilink
minus-squareGuy_Fieris_Hair@lemmy.worldlinkfedilinkarrow-up1·edit-21 year agoy = 1 while y ==1: x = input(“Enter Number”) if int(x) % 2 == 0: print(“EVEN”) else: print(“ODD”) I don’t know why, but I opened up my IDLE for the first time in a year and did it.
minus-squareMrMagnesium12@feddit.delinkfedilinkarrow-up1·1 year agoint val = 3; bool is_odd = val & (decltype(val))0x01 == (decltype (val))1;
minus-squarenero@lemmy.worldlinkfedilinkEnglisharrow-up1·1 year agoKnow you probably don’t care, but you can do a while loop using while True: <code> Which is the same as you using a statement which equals to true. Thought i don’t think you need it for what you’re doing currently.
minus-squarenero@lemmy.worldlinkfedilinkEnglisharrow-up1·1 year agoUnless you want it to keep asking the question of course**
y = 1
while y ==1:
x = input(“Enter Number”)
print(“EVEN”)
print(“ODD”)
I don’t know why, but I opened up my IDLE for the first time in a year and did it.
int val = 3; bool is_odd = val & (decltype(val))0x01 == (decltype (val))1;Know you probably don’t care, but you can do a while loop using while True: <code>
Which is the same as you using a statement which equals to true.
Thought i don’t think you need it for what you’re doing currently.
Unless you want it to keep asking the question of course**